Pr{D2 = 3} = ∑ Pr{D2 = 3|D1 = d1}Pr{D1 = d1} (d1 = 3, 4, 5, 6) and note Pr{D2 = 3|D1 = d1} = 1/d1 since the throw of the 2nd die can be considered as
a markov chain with the following transition matrix: (suppose d1 = 3) 1 2 3 4 5 6 1[ 1 0 0 0 0 0 ] 2[ 0 1 0 0 0 0 ] 3[ 0 0 1 0 0 0 ] 4[1/6 1/6 1/6 1/6 1/6 1/6] 5[1/6 1/6 1/6...