I just want to know if im headed in the right direction. 100.0mls of HCL with a .8402 M concentration is used to dissove an
antacid. 43.50mls of Na(OH) with a 1.105M solution used to neutralize excess acid. millimoles of acid = 100.0mls x .8402M= 84.02 mmoles mmoles of acid neutralized= 43.50mls x 1.105 M= 48.07 mmoles 84.02-48.07= 35.95 mmoles mmoles of acid within the original 100mls ...