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Integral value | Topic profile

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Latest threads on integral value:

RE: How to use an integral for cell output value.

Started 3 days, 13 hours ago (2009-12-16 21:39:00) by Corribus

Ah, I see - I didn't check his formula, just noticed the answers didn't look right. Thank you for the help, that makes sense. "David Biddulph" wrote: > I think that Rik may have intended his formula to be > =SIN(A2*PI()/10)*(A2-A1) > > If you use an interval of 1, as Rik did, the terms of the above formula sum > to 6.313752 > If you change the interval to 0.1, the sum ...

Source: Microsoft Excel forum

Forum: Excel Discussion (Misc queries)

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RE: How to use an integral for cell output value.

Started 3 days, 13 hours ago (2009-12-16 21:39:00) by Corribus

Ah, I see - I didn't check his formula, just noticed the answers didn't look right. Thank you for the help, that makes sense. "David Biddulph" wrote: I think that Rik may have intended his formula to be =SIN(A2*PI()/10)*(A2-A1) If you use an interval of 1, as Rik did, the terms of the above formula sum to 6.313752 If you change the interval to 0.1, the sum becomes 6....

Source: Microsoft Office (Excel, Word) forum - OfficeFrust...

Forum: General Discussion

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RE: How to use an integral for cell output value. in microsoft.public.excel.misc

Started 4 days, 16 hours ago (2009-12-15 18:22:00) by Rik_UK

Not sure if this is right, but by using the equations below the following results are obtained ROW: COL A COL B Fomula in column B 1 0 0 2 1 0.28173 =SIN(A2*PI()*((A2-A1)/COUNT(A:A))) 3 2 0.54064 =SIN(A3*PI()*((A3-A2)/COUNT(A:A))) 4 3 0.75575 =SIN(A4*PI()*((A4-A3)/COUNT(A:A))) 5 4 0.90963 =SIN(A5*PI...

Source: Discussions in microsoft.public.excel.misc

Forum: microsoft.public.excel.misc

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Re: The most accurate integral for the value of pi

Started 2 months, 3 weeks ago (2009-09-29 10:43:00) by g_edgar

Originally Posted by Hurkyl I don't know of any integral-based approximations that are efficient , though. The fastest algorithms tend to be based on infinite sums. On the other hand, I don't...

Source: Physics Help and Math Help - Physics Forums

Forum: Number Theory

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RE: I need to use the int value to declare the array size. However when I try the suggested responses...

Started 2 months, 4 weeks ago (2009-09-22 11:18:00) by millsy5

I need to use the int value to declare the array size. However when I try the suggested responses it does not work. It says "integral constant expression expected" double z = x/y; int a = (int) z; int array1 = [a];

Source: C Board - Your resource for C and C++.

Forum: C Programming

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