Thread: number property question

Ya i too did the same way and sorry to not explain

Thank you all . Your explanations are great,now if I could master it

i think i have it ... so 123^2-123+123^2 is divided by 11? first of all factor 123 out .. 123*(123-1+123) 123*(245) 123/11 =11 + remainder 2 245/11 = 22 remainder 3 2*3 = 6 .... i think thats the way to go ...

^ This is exactly how I did it. For those who are having trouble understanding this, this is how it works; If R is the remainder of the expression ( a*b*c)/n and ar,br,c.r are the remainders when a,b,c are respectively divided by n, then the expression ar*br*critical reasoning/n will give the same remainder as given by a*b*c/n.

Quote: Originally Posted by ace_gre Thank you all . Your explanations are great,now if I could master it I was able to solve this problem by doing the math by hand in about 60 seconds. With problems like this if you don't see the "shortcut" method almost immediately you are better off just crunching the numbers. Paul 123 x 123 = 15129 15129 x 2 = 30258 30258 - 123 = 30135 30135 = 2739 x 11 + 6