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Thread: Determine the de broglie wavelength of an electron accelerated through a potential difference of 110v? - Yahoo! Answers

Started 1 month ago by Haha Fire
need help with this school question plz
Site: Science & Mathematics - Yahoo! Answers  Science & Mathematics - Yahoo! Answers - site profile
Forum: Science & Mathematics   Science & Mathematics  - forum profile
Total authors: 2 authors
Total thread posts: 2 posts
Thread activity: no new posts during last week
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fluxcapa... replied 1 month ago
An electron accelerated through a potential will gain a kinetic energy of 110eV (electron volts). KE = 0.5mv^2 p = mv therefore your momentum, p = sqrt(KE * m *2). To convert electron volts to Joules (SI unit of energy) multiply by 1.6x10^-19. So you have 1.76x10^-17 Joules of energy. The mass of an electron is 9.11x10^-31 kg so; p = 5.66x10^-24 kg m/s the de Broglie ...

 

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fluxcapa...
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Determine the de broglie...
Published (2009-11-11 18:21:00)
An electron accelerated through a potential will gain a kinetic energy of 110eV (electron volts). KE = 0.5mv^2 p = mv therefore your momentum, p = sqrt(KE * m *2). To convert electron volts to Joules (SI unit of energy) multiply by 1.6x10^-19. So you have 1.76x10^-17 Joules of energy. The mass of an electron is 9.11x10^-31 kg so; p = 5.66x10^-24 kg m/s the de Broglie wavelength is equal to planks constant divided by the momentum. h =...
Haha Fire
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user's latest post:
Determine the de broglie...
Published (2009-11-11 18:05:00)
need help with this school question plz

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