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Thread: Abstract Algebra - Cosets

Started 2 months ago by vwishndaetr
Question: Prove the following properties of cosets. Given: Let H be a subgroup and let a and b be elements of G. Statement: The statement is what I have to prove. My issue is I don't know how to start off the problem. When I first looked at the statement. I wanted to say that it is only true when a=b. But there is not talk of the ...
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Total authors: 4 authors
Total thread posts: 8 posts
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HallsofIvy replied 2 months ago
First of all, you need to say "H is a subgroup of G " or the problem doesn't make sense. Now, what is the definition of "aH" and "bH"? Your remark that "I wanted to say that it is only true when a=b" indicates that you are not clear on that definition.

vwishndaetr replied 2 months ago
That means H is a subgroup of G. So clearly stated. a and b are elements of G, and "aH" is a left coset with "a" and "bH" is a left coset with "b."

foxjwill replied 2 months ago
Originally Posted by vwishndaetr a and b are elements of G, and "aH" is a left coset with "a" and "bH" is a left coset with "b." But then what is the definition of a "left coset with a"?

vwishndaetr replied 2 months ago
Originally Posted by foxjwill But then what is the definition of a "left coset with a"? H is a subset. Where h is an element of the set H.

foxjwill replied 2 months ago
Originally Posted by vwishndaetr H is a subset. Where h is an element of the set H. Right. So, what does it mean for the set aH to be equal to the set bH? Oh, and you can type the "in"...

Quantumpencil replied 2 months ago
Remember that aH and bH partition the group (since they are equivalence classes defined by a=b if b = ah for some h in H), if you had any two cosets which had a nonzero intersection, then the transitivity of equivalence classes would automatically make the two equal. So to begin with, you know that if c is in aH, then c equals ah for h in H. if d is in bH, it equals d = bh', for h' in H. Your ...

vwishndaetr replied 2 months ago
Yup thanks. I had one of my professors explain it to me. Forgot to post up. Thanks though! :)

 

Top contributing authors

Name
Posts
vwishndaetr
4
user's latest post:
Abstract Algebra - Cosets
Published (2009-11-05 23:12:00)
Yup thanks. I had one of my professors explain it to me. Forgot to post up. Thanks though! :)
foxjwill
2
user's latest post:
Abstract Algebra - Cosets
Published (2009-11-03 22:52:00)
Originally Posted by vwishndaetr H is a subset. Where h is an element of the set H. Right. So, what does it mean for the set aH to be equal to the set bH? Oh, and you can type the "in" symbol using a "\in" and the "not in" symbol using "otin". I think it formats it better that way.
HallsofIvy
1
user's latest post:
Abstract Algebra - Cosets
Published (2009-11-03 05:17:00)
First of all, you need to say "H is a subgroup of G " or the problem doesn't make sense. Now, what is the definition of "aH" and "bH"? Your remark that "I wanted to say that it is only true when a=b" indicates that you are not clear on that definition.
Quantumpencil
1
user's latest post:
Abstract Algebra - Cosets
Published (2009-11-05 20:55:00)
Remember that aH and bH partition the group (since they are equivalence classes defined by a=b if b = ah for some h in H), if you had any two cosets which had a nonzero intersection, then the transitivity of equivalence classes would automatically make the two equal. So to begin with, you know that if c is in aH, then c equals ah for h in H. if d is in bH, it equals d = bh', for h' in H. Your condition for the equivalence classes...

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