...=(exp(0,5x)) (x+1) où h=g*i, i étant...,5x) (2ax+b) h(x)+2h'(x)= i*(g+2g') + kexp... autres solutions f ? Posons f=g+h. f solution de 2y'+y=(exp(-0,5x))(x...(x)+f(x)=(exp(-0,5x)) (x+1) 2h'(x)+h(x)+2g'(x)+g(x)= (exp(-0,5x))(x+1) or 2h'(x)+h(x)=(exp(-0,5x))(x+1) et g... f=g+h solution de 2y'+t=(exp(-0,5x))(x...
2 months ago
by cmwa93 - 4 posts
http://fr.answers.yahoo.com/question/index?qid=20091210133325AA7M0R7#QZNHWnfZ...
