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GMAT Problem Solving | Forum profile
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Forum profile page for GMAT Problem Solving on http://www.urch.com.
This report page is the aggregated overview from a single forum: GMAT Problem Solving , located on the Message Board at http://www.urch.com.
This forum profile page summarizes the general forum statistics such as: Users Activity, Forum Activity, and Top Authors, which are reported in either a table or graph below for a given reporting time period.
Additional forum profile information for "GMAT Problem Solving " on the Message Board at http://www.urch.com is also shown in the following ways:
1) Latest Active Threads
2) Hot Threads for Last Week
Warning: These statistics are generated using 'best efforts' and can experience delays and reporting errors at times. Please note that such statistics do not constitute a forum's popularity and/or exact posting volumes at any given reporting period.
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Posting activity on GMAT Problem Solving :
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3 Months
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Threads:
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70
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284
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1,135
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Post:
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156
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645
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3,293
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GMAT Problem Solving Posting activity graph:
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Top authors during last week:
user's latest post:
standard daviation
Published (2009-11-12 08:42:00)
Has to be A..simple one
user's latest post:
Geometry Question - Page 2 -...
Published (2009-11-12 15:32:00)
Quote: Originally Posted by arindambanerji I dont get why r u taking BA as 14..I think each tangent should be 14 each and the area = 196pi how can you assume BA = 14???? I didn't assume, i mistook the fact "are 14" . You are rite, each tangent should be 14. And now I'm scare this kind of wordy problem. Thanks for pointing out these facts guys
user's latest post:
ratio
Published (2009-11-12 15:04:00)
A sum of money is divided among A, B and C such that A gets one-third of what B and C together get and B gets two-seventh of what A and C together get. If the amount received by A is $12.4 more than that received by B, find the total amount shared by A, B and C. A. $345.20 B. $386.40 C. $520.30 D. $446.40 E. None
user's latest post:
ratio
Published (2009-11-12 22:36:00)
i dare say that the very problem here is calculation of numbers and wonder how to make it within reasonable period of time a=1/3(b+c) b=2/7(a+c) a=12,4+b 3a=b+c 7b=2a+2c we can get rid off c multiplying the first by 2 and then substraction 9b=8a a=(9/8)*b as a=12,4+b, (9/8)b=12,4+b b=12,4*8=99.2 a=12,4+99,2=111,6 3a=b+c, 3*111,6=99,2+c so c=235,6 99,2+111,6+235,6=446,4 so D dear touche is this gmat problem??? ....i panic
user's latest post:
Geometry Question
Published (2009-11-11 20:53:00)
Quote: Originally Posted by EdYo IMO 7pi r^2 +r^2 = 14 r^2 = 7 area of the cirle = pi*r^2 = 7pi In this case wont r also be equal to 14? I'm i missing something ?
user's latest post:
this question stole from me 5...
Published (2009-11-11 17:42:00)
Wow tricky! I figured out that we only need the radius in 1 minute however could not find way to solve it. Good solution Fever!
user's latest post:
Probability of matched couples
Published (2009-11-05 09:00:00)
Quote: Originally Posted by Sagitha Exactly 60 couples (male-female) are enrolled in a university program. If all the female spouses are in the undergraduate program comprising 700 students, and all the male spouses in the graduate program comprising 300 students, and if one person is to be randomly drawn from each of the two programs, what is the probability that a matched couple was picked? answer is 60/700 * 1/300 and the reasoning given...
user's latest post:
GPREP #3
Published (2009-11-05 06:15:00)
f(2) has no 1 f(3) has nos 2,1 so f(p) has p-1 nos hence 1 is the answer
user's latest post:
need clear explanation
Published (2009-11-04 03:35:00)
Quote: Originally Posted by ahsan400 I think these Column Questions are from GRE. So finsisher's answer, which is A, is correct. Column A has bigger value. finsisher: Can you please explain how you've resolved it? Q:3 We've total numbers = 100 Numbers that are divisible by 5 = 20 Numbers that are divisible by 7 = 14 Numbers that are divisible by both 5 & 7 = 2 Total Numbers that are NOT divisible by 7 & 5 = 100...
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Latest active threads on GMAT Problem Solving ::
Started 4 hours, 35 minutes ago (2009-11-14 16:58:00)
by ojha.abhishek
Hello Zealot, What value we need to find out?
Started 1 day, 22 hours ago (2009-11-12 22:36:00)
by clock60
i dare say that the very problem here is calculation of numbers and wonder how to make it within reasonable period of time
a=1/3(b+c)
b=2/7(a+c)
a=12,4+b
3a=b+c
7b=2a+2c we can get rid off c multiplying the first by 2 and then substraction
9b=8a
a=(9/8)*b
as a=12,4+b,
(9/8)b=12,4+b
b=12,4*8=99.2
a=12,4+99,2=111,6
3a=b+c, 3*111,6=99,2+c
so c=235,6
99,2+111,6+235,6=446...
Started 1 day, 3 hours ago (2009-11-13 18:23:00)
by MBAchase
I solved this, i got (D) i.e 128 answer.
Started 1 day, 2 hours ago (2009-11-13 19:23:00)
by MBAchase
Hi Rohit,
Good Question...
The explanation is below
The eight digit number satisfying the given condition is 99984999 (9998 is twice as large as 4999).
Now, the biggest hint for finding factors of this number is in the question itself.
9998 = 4999 × 2
Multiplying both the sides by 10000, we get,
99980000 = 4999 × 20000
Adding 4999 to both the sides, we get,
99984999 = 4999 × 20000 +...
Started 1 day, 20 hours ago (2009-11-13 01:10:00)
by Brent Hanneson
Magoosh (dot com) has 400+ questions with video solutions for cheap.
Started 1 week ago (2009-11-07 19:46:00)
by touche
4<7-x/3
or 12-7<-x
or -5<-x
or 5>x
1. No
2.|5+3|>2 yes
3.-(4+5) is positive ...No
C
Started 3 days, 3 hours ago (2009-11-11 18:00:00)
by EdYo
IMO B
I just guessed and used my common sense
A. sqrt(3)/4 --> area of a equilateral triangle has the length equal 1 or the radius
B. 1/2 --> area of the iso right triangle with length side is 1 or the radius
C. pi/4 --> 1/4 the area of the circle --> this answer is crazy
D. 1 --> is the area of the triangle has base is the diameter --> against given information
E. sqrt(2) ---> the ...
Started 2 weeks, 6 days ago (2009-10-25 18:13:00)
by StudyGMAT
Squaring both the sides,
17+2( Sqrt 66) = (a+b)+2(sqrt ab)
Therefore, a+b=17 and ab = 66, giving a=11, b=6
Hence, a-b=5
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Hot threads for last week on GMAT Problem Solving ::
Started 3 days, 4 hours ago (2009-11-11 16:59:00)
by ojha.abhishek
In this case, length of the tangent is nothing but the radius of the circle.
So, Area of the Circle will be PI(14)^2 = 3.142*196.
Please share the answer.
Started 1 week ago (2009-11-07 19:46:00)
by touche
4<7-x/3
or 12-7<-x
or -5<-x
or 5>x
1. No
2.|5+3|>2 yes
3.-(4+5) is positive ...No
C
Started 5 days, 4 hours ago (2009-11-09 16:59:00)
by adi_800
(1001^2 - 999^2) / (101^2 - 99^2) = (1000+1)^2 - (1000-1)^2/(100+1)^2 - (100-1)^2
(1000000+1+2000)-(1000000+1-2000)/(10000+1+200)-( 10000+1-200)
Solve the numerator n denominator...
answer is 10..
Started 2 weeks, 2 days ago (2009-10-29 17:43:00)
by touche
soln......vol....... salt......water
6o%.....40 .......24........16
end reqmt
45%......40.......18........22
to reduce 6 of salt drain this
60%.......10........6.........4
bal soln is
60%.......30.......18.......12
add 10 litres dist water and get end reqmt
Started 6 days, 2 hours ago (2009-11-08 19:04:00)
by cristofer
call the prizes x an y and the family members a, b, c. the total number of ways to match family members with prizes is
ax, bx, cx
ay, by, cy,
ax & by, ax & cy
bx & ay, bx & cy
cx & ay, cx & by
12 different ways. (or 3(1) + 3(1) + 3(2))
the total number of ways for 40 people to be matched with two different prizes is
(40)(39) ( permutation formula because order matters)
so the prob ...
Started 3 days, 3 hours ago (2009-11-11 18:00:00)
by EdYo
IMO B
I just guessed and used my common sense
A. sqrt(3)/4 --> area of a equilateral triangle has the length equal 1 or the radius
B. 1/2 --> area of the iso right triangle with length side is 1 or the radius
C. pi/4 --> 1/4 the area of the circle --> this answer is crazy
D. 1 --> is the area of the triangle has base is the diameter --> against given information
E. sqrt(2) ---> the ...
Started 4 days ago (2009-11-10 20:37:00)
by Fiver
We need to find the length of the radius (r) of the circular floor.
Given: pi*r^2-xy = (pi*r^2)/5
4*pi*r^2 = 5xy
therefore r = root(5xy/4*pi)
Answer is B.
Started 4 days, 7 hours ago (2009-11-10 14:29:00)
by adi_800
Started 3 days, 4 hours ago (2009-11-11 17:02:00)
by Zealot
IMO 5m
I would use plugging in here: assume m=60 mins/ 1 hr and c=3
5c=15 in 300 mins/ 5 hrs
plug in the value of m as 60 mins/ 1 hr to check the solution 300 mins/ 5 hrs in the options the answer comes 5m
HTH
Started 1 year, 2 months ago (2008-09-10 05:41:00)
by hawk007
Q13:
If n is the greatest positive integer for which 2^n is a factor of 10!, then n =
A. 2 B. 4 C. 6 D. 8 E. 10
if we take 10! the numbers divisible by 2 are 10.8.6.4.2 so 2.2^3.2.2^2.2
so 1+2+1+3+1->8
so n=8
What is the greatest prime factor of 2^100 - 2^96?
A. 2 B. 3 C. 5 D. 7 E. 11
2^100-2^96=2^96(2^4-1)=2^96(16-1)=2^96(15)
for 15 -3*5,15,1 and the greatest is 5 ...
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