Shell Programming and Scripting | Forum profile

OK now I get what you are driving at. But IMO, the OP did not specify in his first post that there should be a sort on the second field too, plus in his last example he used only sort -u and said it was working fine. That is why I used sort -nu.

Code: awk '/<start>/,/<\/start>/' file.txt

You can do somthing like that : Code: c0=100 c1=12 c2=777 c3=1 clow=$c0 chigh=$c0 (( $c1 < $clow )) && clow=$c1 (( $c2 < $clow )) && clow=$c2 (( $c3 < $clow )) && clow=$c3 (( $c1 > $chigh )) && chigh=$c1 (( $c2 > $chigh )) && chigh=$c2 (( $c3 > $chigh )) && chigh=$c3 echo "Low : $clow"...

That script doesn't call either function.

If you have GNU date you can do something like: Code: date -d "2 month ago" +%F otherwise you can check one of the links of: Yesterdays Date/Date Arithmetic

Try: Code: awk '{ arr[$2]=arr[$2]" "$3; } END { for (i in arr) { print i" "arr[i] >>"Parallel_out"; split(arr[i],ar); printf "%s %.2f",i,(ar[1]+ar[2]+ar[3])/3 >>"avg_out"; }}' < file Output: cat avg_out Quote: 1.0 1.67 4.0 3.73 2.0 3.93 5.0 2.78 3.0 3.41 cat Parallel_out Quote: 1.0 4.00 0.00 1.00 4.0 4.40 4.40...

Code: while read -r line do case "$line" in *barcode* ) li=${line##*barcode } line=${li%%)*} echo "$line" ;; esac done <"file"

Code: sed "s/.*barcode \(.\{6\}\).*/\1/" infile

Thanks to TonyLawrence Code: YOURVAR=$(echo DateFileFormat | sed 's/\./.\\\\/g') our using backticks Code: YOURVAR=`echo DateFileFormat | sed 's/\./.\\\\/g'`

This is an excellent resource about how to use pv, and install pv in different platforms..... A Unix Utility You Should Know About : Pipe Viewer - good coders code, great reuse