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Advanced Physics | Forum profile
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Forum profile page for Advanced Physics on http://www.physicsforums.com.
This report page is the aggregated overview from a single forum: Advanced Physics, located on the Message Board at http://www.physicsforums.com.
This forum profile page summarizes the general forum statistics such as: Users Activity, Forum Activity, and Top Authors, which are reported in either a table or graph below for a given reporting time period.
Additional forum profile information for "Advanced Physics" on the Message Board at http://www.physicsforums.com is also shown in the following ways:
1) Latest Active Threads
2) Hot Threads for Last Week
Warning: These statistics are generated using 'best efforts' and can experience delays and reporting errors at times. Please note that such statistics do not constitute a forum's popularity and/or exact posting volumes at any given reporting period.
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Posting activity on Advanced Physics:
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3 Months
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Threads:
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176
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627
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1,848
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Post:
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432
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1,708
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4,843
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Advanced Physics Posting activity graph:
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Top authors during last week:
user's latest post:
a problem on the paraxial wave...
Published (2009-11-28 23:25:00)
Originally Posted by jeebs so the second derivatives with respect to x and y are zero, don't know if this has any significance?. No. is a function , and , so the second derivatives with respect to and should not be zero.
user's latest post:
2 Qs in QM.
Published (2009-11-28 12:59:00)
Ok, I solved it, because <H(a)>>=E0 for any a>0, then for a=0 0>=<H(0)>>=E0, so there is at least one bound state mainly the ground state.
user's latest post:
Derive the Period of an...
Published (2009-11-26 18:32:00)
Hi SpringPhysics! Originally Posted by SpringPhysics … I substitute that into the PE-KE equation, and then I'm stuck. What do I do next? Sorry, you've lost me … what is the PE-KE equation you got stuck with?
user's latest post:
Re: Derive the Period of an...
Published (2009-11-26 21:06:00)
torque o.0... Nevertheless, I finally got the answer lol. Thanks for your help guys
user's latest post:
The Hamiltonian vs. the energy...
Published (2009-11-27 04:54:00)
Thank you for clarifying this. Could you elaborate more about what you meant with the legendere transform?
user's latest post:
Freq response of forced...
Published (2009-11-28 16:03:00)
For complex amplitudes, one squares the absolute value of the amplitude to get the power response.
user's latest post:
Simple Harmonic Oscillator -...
Published (2009-11-27 17:42:00)
No your answer doesn't make sense. The energy should be position independent.
user's latest post:
a problem on the paraxial wave...
Published (2009-11-28 23:22:00)
You need to remember that both and are functions of the position vector (and hence , and )....so when you are taking spatial derivatives of the product of either of these functions with say, , you need to use the product rule. For example,
user's latest post:
Another 2 questions in...
Published (2009-11-28 16:11:00)
For #1, you can't just assume that whenever . Remember how you compute a matrix element:
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Latest active threads on Advanced Physics::
Started 2 days, 7 hours ago (2009-11-28 09:09:00)
by kuruman
Originally Posted by Bizkit
1. The problem statement, all variables and given/known data
A 1.5 m 3 tank containing air at 35°C and 750 kPa is connected by a valve to another tank containing 8.25 kg of air at 65°C and 265 kPa. Now the ...
Started 1 day, 17 hours ago (2009-11-28 23:22:00)
by gabbagabbahey
You need to remember that both and are functions of the position vector (and hence , and )....so when you are taking spatial derivatives of the product of either of these functions with say, , you need to use the product rule.
For example,
Started 2 days, 22 hours ago (2009-11-27 18:23:00)
by Redbelly98
Welcome to Physics Forums! And sorry for the delay in responding.
Up until the last 10 minutes, I was not familiar with this type of problem. After a google search, I am now familiar with two ways to solve this problem.
One way is the way you did it, but they don't seem to want that. The other way is shown here, look at the equation for Z eff :
http://www.physicsforums.com/...
Started 2 days, 1 hour ago (2009-11-28 14:49:00)
by JaWiB
It seems strange to me that AC power consumption changes with the fuel consumption. It seems like it should be relatively constant for a constant setting (unless your car has climate control and you can set the a desired temperature). That is, I would think more fuel would go to keeping the car moving at higher speeds than would go to keeping the inside cool...
Started 2 days ago (2009-11-28 16:02:00)
by Redbelly98
Since the question indicates these are hydrogen atoms , it is not considered a diatomic gas in this case.
Try looking up Boltzmann Factors in your textbook.
Started 2 days ago (2009-11-28 16:11:00)
by diazona
For #1, you can't just assume that whenever . Remember how you compute a matrix element:
Started 2 days ago (2009-11-28 16:03:00)
by Redbelly98
For complex amplitudes, one squares the absolute value of the amplitude to get the power response.
Started 2 days, 5 hours ago (2009-11-28 11:25:00)
by ehild
"0.8= vb'-va' /2" is wrong. (vb'-va')/4 = 0.8.
ehild
Started 2 days, 2 hours ago (2009-11-28 14:38:00)
by JaWiB
I don't know how to do the problem, but I do know that you made a mistake when you multiplied the numerator by the complex conjugate of the denominator. The i's don't go away for the numerator.
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Hot threads for last week on Advanced Physics::
Started 6 days, 8 hours ago (2009-11-24 07:54:00)
by tiny-tim
Hi SpringPhysics!
(have an alpha: α and an omega: ω and a theta: θ and try using the X 2 tag just above the Reply box )
Yes, conservation of mechanical energy should give you θ' 2 + f(θ) = constant …
the question says "at small angles", so now replace cos or sin by polynomials, and integrate.
(btw, it isn't (R-r)sinθ, it's (R-r)(1-cosθ))
Started 1 week ago (2009-11-23 11:25:00)
by estalas
Originally Posted by Doc Al
Your problem description is not quite clear. I assume that the problem begins with a ball at rest on a platform (on top of a frictionless surface)? And that you need the minimum coefficient of friction so that ...
Started 6 days, 8 hours ago (2009-11-24 07:54:00)
by Loxias
never mind.. i just noticed it..
Started 3 days, 8 hours ago (2009-11-27 08:11:00)
by jdwood983
Originally Posted by MathematicalPhysicist
3. I am not sure, but I think I need to expand dV by r>>R0, but after that I don't know how to procceed.
Any hints?
What is the equation to find ...
Started 3 days, 1 hour ago (2009-11-27 15:00:00)
by jdwood983
For #2 you should start with Schrodinger's equation:
And work from there.
Started 6 days, 23 hours ago (2009-11-23 16:48:00)
by ricof
I should add that I have absolutely no idea where or how the 1.2kg of nitrogen comes in to the equation, nor if V1 is in fact 1.
Please help me i've been staring at this one for hours!
Started 5 days, 8 hours ago (2009-11-25 08:07:00)
by Mapes
Looks to me like part (c) requires you to develop a differential equation describing the heat transfer. Can you perform an energy balance on a slice of the rod showing the inputs and outputs from conduction and convection?
Started 5 days, 1 hour ago (2009-11-25 15:32:00)
by Feldoh
It's a Gaussian integral that comes out to be
Started 6 days, 1 hour ago (2009-11-24 15:35:00)
by Feldoh
I think your professor is trying to say something like this:
If we have because y commutes can just be factored out.
Started 3 days, 19 hours ago (2009-11-26 21:26:00)
by Feldoh
Well, I didn't check your math but it seems that your Hamiltonian does not include the potential energy for the harmonic oscillator.
I think you should get something proportional to
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