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The tendency of angle to rotate is somewhat prevented by the brick. However, I think you can resolve the torsion into shear and add it to the shear produced by weight, then check combined shear and bending stresses.

( I seldom do hourly as I am mainly in analysis and design.   Usually bid set fee for larger jobs, or not to exceed based on an hourly for small jobs or removations.   In order to get some work, I have had to adjust my hourly fees to about 85% of a year ago.  Really competitive here. My business revenue has declined to about 20 percent of what it was a year...

As a last resort, if after your previous investigation you estimate the design can provide a ductile behaviour to the limit state, you can load it to a level equivalent to that of use to ensure by this proof the behaviour will remain sound.

( Quote: Is the steel angle required to have some type of lateral-restraint because if an angle just bears on the brick how is the torsional restraint achieved at the ends? If the brick above the opening aligns with the supporting brick, torsional restraint is not required at the ends because the reaction is centered on the brick, i.e. the bearing pressure under gravity load is uniform. The torsional moment in the angle at the support is R*e...

I am almost exclusively hourly, with an occasion "cost of construction" fee base.  I also do a reasonable number of "lump sum" fees, as long as I can clearly define the scope of work. I don't do much "design" work.  I do mostly failure analysis and investigation (forensic work), so we don't usually know for sure what we'll encounter or how long it will...

I would say top of paving.

Also, be sure (like the example notes) to check leg local buckling since the toe of the angle is in compression.  

As a rule of thumb we used to use 10 times the thickness of the slab in each direction.

Check out this paper. http://files.engineering.com/getfile.aspx?folder=b4e286ab-5391-4b2a-be90-7a

Thanks Stillerz, I just read Example F.11 and the problem has to assume  bending about the geometric axis. From there I gathered that the loading was through the shear center. Thanks for the help guys and/or gals. I have enough information for what I have been looking for.