Started 3 days, 21 hours ago (2009-11-22 23:24:00)
by Borek
How much water was consumed by the reaction? And read answer here: http://www.chemicalforums.com/index.php?topic=3668 8.0
Started 1 week, 3 days ago (2009-11-16 01:46:00)
by Borek
What are these numbers? (list values)
Started 3 days, 20 hours ago (2009-11-22 23:58:00)
by Borek
Quote from: Roderick on Yesterday at 05:56:42 PM In calculating the end point it is my understanding that you need [I-]/[HI]=1/10 and setting this to [NaOH]/(3.07x10 -1 ) to solve for [NaOH]. Please eleaborate - I think I know what you are aiming at, but I don't want to guess. Quote I did this and got 3.7x10 -2 M NaOH as
the final answer. Is this correct? No, you are not in a correct ...
Started 3 days, 20 hours ago (2009-11-22 23:46:00)
by Borek
0.0297g seems OK. How many moles of acid will you need in
the final solution? Assume volume (500 mL) will not change - you will be able to check it later comparing initial volume with the volume acid added (if the latter is much smaller, it can be ignored).
Started 2 days, 19 hours ago (2009-11-24 01:21:00)
by Borek
Started 2 days, 19 hours ago (2009-11-24 01:19:00)
by Borek
In low pH PO 4 3- gets protonated.
Started 6 days, 9 hours ago (2009-11-20 11:21:00)
by sjb
What is the definition of a pure
covalent bond?
Started 1 week ago (2009-11-19 16:24:00)
by The Cancer Curer
I wouldn't ask "How much is your salary," that is pretty personal along with "how much is your max salary in the future" and "how many years do you need to reach for max salaries" and "how much was your starting salary." I would stick to asking something like, "what pathway did you take to reach your current position (what degree do you have, did you
shadow people for experience, etc)?" or ...
Started 1 week ago (2009-11-19 15:30:00)
by The Cancer Curer
Are you sure this is all of the reaction?...It appears that a
reactant is missing - the hydrogen.
Started 1 week ago (2009-11-18 22:15:00)
by Borek
Quote from: Shaun1979 on Yesterday at 09:52:04 PM I found this on the internet as answers: 2Cu + O2 = CuO (
Copper (II) Oxide) OR 4Cu + O2 = Cu2O (Copper (I) Oxide) Don't believe everything on interenet - neither of these reactions is correctly balanced.